1912 United States presidential election in Oregon

1912 United States presidential election in Oregon

← 1908 November 5, 1912 1916 →
 
Nominee Woodrow Wilson Theodore Roosevelt
Party Democratic Progressive
Home state New Jersey New York
Running mate Thomas R. Marshall Hiram Johnson
Electoral vote 5 0
Popular vote 47,064 37,600
Percentage 34.34% 27.44%

 
Nominee William Howard Taft Eugene V. Debs
Party Republican Socialist
Home state Ohio Indiana
Running mate Nicholas M. Butler Emil Seidel
Electoral vote 0 0
Popular vote 34,673 13,343
Percentage 25.30% 9.74%

County Results

President before election

William Howard Taft
Republican

Elected President

Woodrow Wilson
Democratic

The 1912 United States presidential election in Oregon took place on November 5, 1912, as part of the 1912 United States presidential election. State voters chose five representatives, or electors, to the Electoral College, who voted for president and vice president.

Oregon was won by Princeton University President Woodrow Wilson (DVirginia), running with governor of Indiana Thomas R. Marshall, with 34.34% of the popular vote, against the 26th president of the United States Theodore Roosevelt (PNew York), running with California Governor Hiram Johnson, with 27.44% of the popular vote, the 27th president of the United States William Howard Taft (ROhio), running with Columbia University President Nicholas Murray Butler, with 25.30% of the popular vote and the five-time candidate of the Socialist Party of America for President of the United States Eugene V. Debs (SIndiana), running with the first Socialist mayor of a major city in the United States Emil Seidel, with 9.74% of the popular vote.[1]

As a result of his win, Wilson became the first Democratic presidential candidate since Horatio Seymour in 1868 to win Oregon.

As of the 2020 presidential election, this is the only election where Oregon voted Democratic while neighboring Washington didn't.

  1. ^ "1912 Presidential Election Results – Oregon". Dave Leip’s U.S. Election Atlas.

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