1928 United States Senate elections

1928 United States Senate elections

← 1926 November 6, 1928[1] 1930 →

32 of the 96 seats in the United States Senate
49 seats needed for a majority
  Majority party Minority party
 
Leader Charles Curtis
(retired)
Joseph Robinson
Party Republican Democratic
Leader since November 9, 1924 December 3, 1923
Leader's seat Kansas Arkansas
Seats before 49 46
Seats after 56 39
Seat change Increase 7 Decrease 7
Seats up 12 19
Races won 18 13

  Third party
 
Party Farmer–Labor
Seats before 1
Seats after 1
Seat change Steady
Seats up 1
Races won 1

Results of the elections:
     Democratic hold
     Republican gain      Republican hold
     Farmer–Labor hold
     No election

Majority Leader before election

Charles Curtis
Republican

Elected Majority Leader

James Watson
Republican

The 1928 United States Senate elections were elections that coincided with the presidential election of Republican Herbert Hoover. The 32 seats of Class 1 were contested in regular elections, and special elections were held to fill vacancies. The strong economy helped the Republicans to gain seven seats from the Democrats.

Senate Majority leader, Republican Charles Curtis of Kansas, was not up for election this cycle, but he was elected U.S. Vice President. He resigned March 3, 1929, so his seat was vacant at the beginning of the next Congress until April 1, 1929, when a Republican was appointed to continue the term.

  1. ^ September 10, 1928, in Maine

© MMXXIII Rich X Search. We shall prevail. All rights reserved. Rich X Search