1948 United States presidential election in Ohio

1948 United States presidential election in Ohio

← 1944 November 2, 1948 1952 →
 
Nominee Harry S. Truman Thomas E. Dewey
Party Democratic Republican
Home state Missouri New York
Running mate Alben W. Barkley Earl Warren
Electoral vote 25 0
Popular vote 1,452,791 1,445,684
Percentage 49.48% 49.24%

County Results

President before election

Harry S. Truman
Democratic

Elected President

Harry S. Truman
Democratic

The 1948 United States presidential election in Ohio was held on November 2, 1948 as part of the 1948 United States presidential election. State voters chose 25 electors to the Electoral College, who voted for president and vice president.

Ohio was narrowly won by Democratic Party candidate, incumbent President Harry S. Truman with 49.48% of the popular vote. Republican Party candidate Thomas E. Dewey received 49.24% of the popular vote. The state had previously gone to Dewey against Franklin D. Roosevelt four years earlier.

As of the 2020 presidential election, this is the last time a Democrat won Ohio but lost neighboring Pennsylvania consequently it is also the last time Ohio voted more Democratic than Pennsylvania.. This was the closest margin of any state in the election.[1]

This was one of five states flipped by Truman (the others being Colorado, Iowa, Wisconsin, & Wyoming), and one of 18 states that changed party overall.

  1. ^ "1948 Presidential General Election Data – National". Dave Leip’s U.S. Election Atlas.

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