1948 United States presidential election in Washington (state)

1948 United States presidential election in Washington (state)

← 1944 November 2, 1948[1] 1952 →

All 8 Washington votes to the Electoral College
 
Nominee Harry S. Truman Thomas Dewey
Party Democratic Republican
Home state Missouri New York
Running mate Alben W. Barkley Earl Warren
Electoral vote 8 0
Popular vote 475,165 386,314
Percentage 52.56% 42.73%

County Results

President before election

Harry S. Truman
Democratic

Elected President

Harry S. Truman
Democratic

The 1948 United States presidential election in Washington took place on November 2, 1948, as part of the 1948 United States presidential election. Voters chose eight[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Washington was won by incumbent President Harry S. Truman (DMissouri), running with Kentucky Senator Alben W. Barkley, with 52.61 percent of the popular vote, against Governor Thomas Dewey (RNew York), running with California Governor Earl Warren, with 42.68 percent of the popular vote.[3][4]

As of the 2020 presidential election, this is the last occasion Lincoln County has voted for a Democratic Presidential candidate.[5]

  1. ^ "United States Presidential election of 1948 - Encyclopædia Britannica". Retrieved October 31, 2017.
  2. ^ "1948 Election for the Forty-First Term (1949-53)". Retrieved October 31, 2017.
  3. ^ "1948 Presidential General Election Results - Washington". Retrieved October 31, 2017.
  4. ^ "The American Presidency Project - Election of 1948". Retrieved October 31, 2017.
  5. ^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

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