1984 United States presidential election in Rhode Island

1984 United States presidential election in Rhode Island

← 1980 November 6, 1984 1988 →
Turnout78.0%[1] Decrease 1.0 pp
 
Nominee Ronald Reagan Walter Mondale
Party Republican Democratic
Home state California Minnesota
Running mate George H. W. Bush Geraldine Ferraro
Electoral vote 4 0
Popular vote 212,080 197,106
Percentage 51.66% 48.02%


President before election

Ronald Reagan
Republican

Elected President

Ronald Reagan
Republican

The 1984 United States presidential election in Rhode Island took place on November 6, 1984. All 50 states and the District of Columbia, were part of the 1984 United States presidential election. Voters chose four electors to the Electoral College, which selected the president and vice president of the United States.

Rhode Island was won by incumbent United States President Ronald Reagan of California, who was running against former Vice President Walter Mondale of Minnesota. Reagan ran for a second time with incumbent Vice President and former C.I.A. Director George H. W. Bush of Texas, and Mondale ran with Representative Geraldine Ferraro of New York, the first major female candidate for the vice presidency. Rhode Island is 1 of 6 States that voted for Reagan in 1984 and have not voted Republican in any presidential race since; the other 5 are Washington, Hawaii, Massachusetts, New York, and Oregon. This was also the last time that the counties of Bristol, Newport and Washington voted for a Republican presidential candidate and the last time a Republican presidential candidate won Kent County or any county in the state until Donald Trump won it in 2016.

  1. ^ This figure is calculated by dividing the total number of votes cast in 1984 (422,851) by an estimate of the number of registered voters in Rhode Island in 1984 (542,216). See "General Election November 2, 1984". Rhode Island Board of Elections. Retrieved February 6, 2018.

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