1992 United States presidential election in Mississippi

1992 United States presidential election in Mississippi

← 1988 November 3, 1992 1996 →
 
Nominee George H. W. Bush Bill Clinton Ross Perot
Party Republican Democratic Independent
Home state Texas Arkansas Texas
Running mate Dan Quayle Al Gore James Stockdale
Electoral vote 7 0 0
Popular vote 487,793 400,258 85,626
Percentage 49.68% 40.77% 8.72%

County Results

President before election

George H. W. Bush
Republican

Elected President

Bill Clinton
Democratic

The 1992 United States presidential election in Mississippi took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.

Mississippi was won by incumbent President George H. W. Bush (R-Texas) with 49.68% of the popular vote over Governor Bill Clinton (D-Arkansas) with 40.77%. Businessman Ross Perot (I-Texas) finished in third, with 8.72% of the popular vote.[1] Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot.[1]

  1. ^ a b "1992 Presidential General Election Results – Mississippi". Dave Leip’s U.S. Election Atlas. Retrieved June 8, 2012.

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