1996 United States presidential election in Oregon

1996 United States presidential election in Oregon
Clinton 40-50% 50-60%	Dole 40-50% 50-60% 60-70%
President before election; Bill Clinton; Democratic	Elected President ; Bill Clinton; Democratic

The 1996 United States presidential election in Oregon took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.

Oregon was won by President Bill Clinton (D) over Senator Bob Dole (R-Kansas), with Clinton winning 47.2% to 39.1% for a margin of 8.1%. Billionaire businessman Ross Perot (Reform-Texas) finished in third, with 8.8% of the popular vote.^[1]

Oregon was one of thirteen states where, on the election ballot, James Campbell of California, Perot’s former boss at IBM, was listed as a stand-in candidate for vice president.^[2]

As of the 2020 presidential election^[update], this is the last occasion when the Democratic nominee has carried Gilliam, Morrow and Coos Counties.^[3] It is also the last time any Eastern Oregon county voted for the Democratic candidate.

^ Cite error: The named reference Leip was invoked but never defined (see the help page).
^ "Perot Names Stand-in Veep Candidate". CNN.com. August 21, 1996. Archived from the original on May 17, 2008. Retrieved June 11, 2012.
^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

[Leip-1] Cite error: The named reference Leip was invoked but never defined (see the help page).

[Campbell-2] "Perot Names Stand-in Veep Candidate". CNN.com. August 21, 1996. Archived from the original on May 17, 2008. Retrieved June 11, 2012.

[How-3] Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

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