Ferdinand, Idaho

Ferdinand, Idaho
Location of Ferdinand in Idaho County, Idaho.
Location of Ferdinand in Idaho County, Idaho.
Coordinates: 46°9′10″N 116°23′26″W / 46.15278°N 116.39056°W / 46.15278; -116.39056
CountryUnited States
StateIdaho
CountyIdaho
Government
 • MayorGabriel Riener
Area
 • Total0.17 sq mi (0.45 km2)
 • Land0.17 sq mi (0.45 km2)
 • Water0.00 sq mi (0.00 km2)
Elevation
3,720 ft (1,130 m)
Population
 • Total159
 • Estimate 
(2019)[3]
162
 • Density925.71/sq mi (358.13/km2)
Time zoneUTC-8 (Pacific (PST))
 • Summer (DST)UTC-7 (PDT)
ZIP code
83526
Area code208
FIPS code16-27460
GNIS feature ID0396483

Historical population
CensusPop.Note
1920255
1930196−23.1%
194022313.8%
1950206−7.6%
1960176−14.6%
1970157−10.8%
1980144−8.3%
1990135−6.2%
20001457.4%
20101599.7%
2019 (est.)162[3]1.9%
U.S. Decennial Census[4]

Ferdinand is a city in Idaho County, Idaho, United States. The population was 159 at the 2010 census, up from 145 in 2000. At the southern end of the Nez Perce Indian Reservation, it was founded by F.M. Bieker shortly after the reservation was opened for settlement in 1895. It was named after Ferdinand, Indiana, where his mother's family had lived.[5]

  1. ^ "2019 U.S. Gazetteer Files". United States Census Bureau. Retrieved July 9, 2020.
  2. ^ Cite error: The named reference wwwcensusgov was invoked but never defined (see the help page).
  3. ^ a b "Population and Housing Unit Estimates". United States Census Bureau. May 24, 2020. Retrieved May 27, 2020.
  4. ^ "Census of Population and Housing". Census.gov. Retrieved June 4, 2015.
  5. ^ "Lost map set stage for location of Ferdinand". Lewiston Morning Tribune. October 6, 1955. p. 6-LCSE.

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