Jefferson, Ohio

Jefferson, Ohio
Ashtabula County Courthouse
Location of Jefferson, Ohio
Location of Jefferson, Ohio
Location of Jefferson in Ashtabula County
Location of Jefferson in Ashtabula County
Coordinates: 41°44′19″N 80°45′25″W / 41.73861°N 80.75694°W / 41.73861; -80.75694
CountryUnited States
StateOhio
CountyAshtabula
Area
 • Total2.54 sq mi (6.57 km2)
 • Land2.54 sq mi (6.57 km2)
 • Water0.00 sq mi (0.00 km2)
Elevation961 ft (293 m)
Population
 (2020)
 • Total3,226
 • Density1,271.58/sq mi (491.04/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
ZIP code
44047
Area code440
FIPS code39-38500[3]
GNIS feature ID1042061[2]
Websitehttp://www.jeffersonohio.us/

Jefferson is a village in and the county seat of Ashtabula County, Ohio, United States. The population was 3,226 at the 2020 census.[4] It is part of the Ashtabula micropolitan area, 50 miles (80 km) northeast of Cleveland.

Modern-day Jefferson sports the world's only perambulator museum and a historical complex including several restored 19th-century buildings. Joshua Giddings' law office has also been restored as a museum. Annual village events include the Ashtabula County Fair, the Strawberry Festival, Jefferson Days, and the Covered Bridge Festival.

  1. ^ "ArcGIS REST Services Directory". United States Census Bureau. Retrieved September 20, 2022.
  2. ^ a b U.S. Geological Survey Geographic Names Information System: Jefferson, Ohio
  3. ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
  4. ^ "Find a County". National Association of Counties. Archived from the original on May 31, 2011. Retrieved June 7, 2011.

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