1836 United States presidential election in Vermont

1836 United States presidential election in Vermont

← 1832 November 3 - December 7, 1836 1840 →

Nominee William Henry Harrison Martin Van Buren Party Whig Democratic Home state Ohio New York Running mate Francis Granger Richard Mentor Johnson Electoral vote 7 0 Popular vote 20,994 14,037 Percentage 59.93% 40.07%

County results Harrison   50-60%   60-70%   70-80% Van Buren   50-60%

President before election Andrew Jackson Democratic Elected President Martin Van Buren Democratic

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Ballot Measures 2022 Proposal 5
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v t e

The 1836 United States presidential election in Vermont took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for Whig candidate William Henry Harrison over Democratic candidate Martin Van Buren. Harrison won Vermont by a margin of 19.86%.

This would be the final time a Democratic candidate would carry Essex County until Franklin D. Roosevelt won it 104 years later in 1940.

1836 would stand as the strongest performance for a Democratic candidate in Vermont until 96 years later in 1932, when Franklin D. Roosevelt performed slightly better with 41.08%.

Harrison would later win Vermont again four years later when he successfully defeated Van Buren.