1846 United States House of Representatives election in Florida

1846 United States House of Representatives election in Florida

← 1845 (special) October 5, 1846 1848 →
 
Nominee Edward Carrington Cabell William A. Kain
Party Whig Democratic
Popular vote 2,990 2,887
Percentage 50.88% 49.12%

County results
Cabell:      50–59%      60–69%      70–79%
Kain:      50–59%      60–69%      70–79%      80–89%
     Tie
     No Votes

Representative before election

William Henry Brockenbrough
Democratic

Elected Representative


Edward Carrington Cabell
Whig

The 1846 United States House of Representatives election in Florida was held on Monday, October 5, 1846 to elect the single United States Representative from the state of Florida, one from the state's single at-large congressional district, to represent Florida in the 30th Congress. The election coincided with the elections of other offices, including various state and local elections. The party primaries were held on June 20, 1846.[1]

The winning candidate would serve a two-year term in the United States House of Representatives from March 4, 1847, to March 4, 1849.

  1. ^ "Our Campaigns - FL At Large Race - Oct 05, 1846". www.ourcampaigns.com. Retrieved October 16, 2020.

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