1849 Connecticut gubernatorial election

1849 Connecticut gubernatorial election

← 1848 April 2, 1849 1850 →

Nominee Joseph Trumbull Thomas H. Seymour John M. Niles Party Whig Democratic Free Soil Electoral vote 122 110 Popular vote 27,800 25,018 3,520 Percentage 49.35% 44.41% 6.25%

County results Trumbull:      40–50%      50–60% Seymour:      40–50%

Governor before election Clark Bissell Whig Elected Governor Joseph Trumbull Whig

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v t e

The 1849 Connecticut gubernatorial election was held on April 2, 1849.^[1] Former congressman and Whig nominee Joseph Trumbull defeated former congressman and Democratic nominee Thomas H. Seymour as well as former Senator and Free Soil nominee John M. Niles with 49.35% of the vote. Niles had previously been the Democratic nominee for this same office in 1840.

Trumbull won a plurality of the vote, but fell short of a majority. As a result, the Connecticut General Assembly elected the governor, per the state constitution. Trumbull won the vote over Seymour 122 to 110 in the General Assembly, and became the governor.^[2] This was the first of six consecutive elections in which the Free Soil Party participated.