1876 United States presidential election in Vermont

1876 United States presidential election in Vermont

← 1872 November 7, 1876 1880 →
 
Nominee Rutherford B. Hayes Samuel J. Tilden
Party Republican Democratic
Home state Ohio New York
Running mate William A. Wheeler Thomas A. Hendricks
Electoral vote 5 0
Popular vote 44,091 20,254
Percentage 68.30% 31.38%

County Results
Hayes
  50–60%
  60–70%
  70–80%
  80–90%


President before election

Ulysses S. Grant
Republican

Elected President

Rutherford B. Hayes
Republican

The 1876 United States presidential election in Vermont took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont voted for the Republican nominee, Rutherford B. Hayes, over the Democratic nominee, Samuel J. Tilden. Hayes won Vermont by a margin of 36.92%.

With 68.30% of the popular vote, Vermont would be Hayes' strongest victory in terms of percentage in the popular vote.[1]

  1. ^ "1876 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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