1880 United States presidential election in Rhode Island

1880 United States presidential election in Rhode Island

← 1876 November 2, 1880 1884 →

Nominee James A. Garfield Winfield S. Hancock Party Republican Democratic Home state Ohio Pennsylvania Running mate Chester A. Arthur William H. English Electoral vote 4 0 Popular vote 18,195 10,779 Percentage 62.24% 36.87%

County Results Garfield   50-60%   60-70%

President before election Rutherford B. Hayes Republican Elected President James A. Garfield Republican

Elections in Rhode Island
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Ballot measures 2020 Question 1
Providence Mayoral elections 1998 2002 2006 2010 2014 2018 2022
v t e

The 1880 United States presidential election in Rhode Island took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Rhode Island voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won the state by a margin of 25.37%.

With 62.24% of the popular vote, Rhode Island would be Garfield's fourth strongest victory in terms of percentage in the popular vote after Vermont, Nebraska and Minnesota.^[1]