1880 United States presidential election in Vermont

1880 United States presidential election in Vermont

← 1876 November 2, 1880 1884 →
 
Nominee James A. Garfield Winfield S. Hancock
Party Republican Democratic
Home state Ohio Pennsylvania
Running mate Chester A. Arthur William H. English
Electoral vote 5 0
Popular vote 45,091 18,182
Percentage 69.81% 28.15%

County Results
Garfield
  60–70%
  70–80%
  80–90%


President before election

Rutherford B. Hayes
Republican

Elected President

James A. Garfield
Republican

The 1880 United States presidential election in Vermont took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won Vermont by a margin of 41.66%.

With 69.81% of the popular vote, Vermont would be Garfield's strongest victory in terms of percentage in the popular vote.[1]

The Republican vice presidential nominee Chester Alan Arthur was born in Vermont, more specifically in the town of Fairfield.

  1. ^ "1880 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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