1884 United States presidential election in West Virginia

1884 United States presidential election in West Virginia

← 1880 November 4, 1884 1888 →
Turnout21.37% of the total population Increase 3.16 pp[1]
 
Nominee Grover Cleveland James G. Blaine
Party Democratic Republican
Home state New York Maine
Running mate Thomas A. Hendricks John A. Logan
Electoral vote 6 0
Popular vote 67,311 63,096
Percentage 50.94% 47.75%

County Results

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in West Virginia took place on November 4, 1884, as part of the 1884 United States presidential election. West Virginia voters chose six representatives, or electors, to the Electoral College, who voted for president and vice president.[2]

West Virginia was won by Grover Cleveland, the 28th governor of New York, (DNew York), running with the former governor of Indiana Thomas A. Hendricks, with 50.94 percent of the popular vote, against Secretary of State James G. Blaine (R-Maine), running with Senator John A. Logan, with 47.75 percent of the vote.[2]

The Prohibition Party chose John St. John, the former governor of Kansas, and former Maryland State Senator William Daniel as their presidential and vice-presidential candidates and received 0.71 percent of the vote. The Greenback and Anti-Monopoly Parties both chose major general and former governor of Massachusetts Benjamin Butler and Absolom M. West, an unseated Mississippi representative, received 0.60 percent of the vote.

This would prove the last time the Democratic Party won an absolute majority of West Virginia’s popular vote until 1932.

  1. ^ "1884 Presidential Election Results – West Virginia: Total Population Turnout".
  2. ^ a b "1884 Presidential Election Results — West Virginia".

© MMXXIII Rich X Search. We shall prevail. All rights reserved. Rich X Search