1888 United States presidential election in Maine

1888 United States presidential election in Maine

← 1884 November 6, 1888 1892 →
 
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Levi P. Morton Allen G. Thurman
Electoral vote 6 0
Popular vote 73,730 50,472
Percentage 57.49% 39.35%

County Results
Harrison
  50-60%
  60-70%


President before election

Grover Cleveland
Democratic

Elected President

Benjamin Harrison
Republican

The 1888 United States presidential election in Maine took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.

Maine voted for the Republican nominee, Benjamin Harrison, over the Democratic nominee, incumbent President Grover Cleveland. Harrison won the state by a margin of 18.14%.

With 57.49% of the popular vote, Maine would prove to be Harrison's third strongest victory in terms of percentage in the popular vote after Vermont and Nevada.[1]

  1. ^ "1888 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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