1888 United States presidential election in Vermont

1888 United States presidential election in Vermont

← 1884 November 6, 1888 1892 →
 
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Levi P. Morton Allen G. Thurman
Electoral vote 4 0
Popular vote 45,192 16,788
Percentage 69.05% 25.65%

County Results
Harrison
  60-70%
  70-80%
  80-90%


President before election

Grover Cleveland
Democratic

Elected President

Benjamin Harrison
Republican

The 1888 United States presidential election in Vermont took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont voted for the Republican nominee, Benjamin Harrison, over the Democratic nominee, incumbent President Grover Cleveland. Harrison won Vermont by a margin of 43.40%.

With 69.05% of the popular vote, Vermont would be Harrison's strongest victory in terms of percentage in the popular vote.[1]

Vice President-elect Levi P. Morton was born in Shoreham, Vermont.

  1. ^ "1888 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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