1892 United States presidential election in Maine

1892 United States presidential election in Maine

← 1888 November 8, 1892 1896 →
 
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Whitelaw Reid Adlai Stevenson I
Electoral vote 6 0
Popular vote 62,936 48,049
Percentage 54.05% 41.26%

County Results
Harrison
  40-50%
  50-60%
  60-70%


President before election

Benjamin Harrison
Republican

Elected President

Grover Cleveland
Democratic

The 1892 United States presidential election in Maine took place on November 8, 1892, as part of the 1892 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.

Maine voted for the Republican nominee, incumbent president Benjamin Harrison, over the Democratic nominee, former president Grover Cleveland, who was running for a second, non-consecutive term. Harrison won the state by a margin of 12.79%.

With 54.05% of the popular vote, Maine would prove to be Harrison's second strongest victory in terms of percentage of the popular vote after Vermont.[1]

  1. ^ "1892 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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