1908 United States presidential election in Vermont

1908 United States presidential election in Vermont

← 1904 November 3, 1908 1912 →

Nominee William Howard Taft William Jennings Bryan Party Republican Democratic Home state Ohio Nebraska Running mate James S. Sherman John W. Kern Electoral vote 4 0 Popular vote 39,552 11,496 Percentage 75.08% 21.82%

County Results Taft   60-70%   70-80%   80-90%

President before election Theodore Roosevelt Republican Elected President William Howard Taft Republican

Elections in Vermont
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Ballot Measures 2022 Proposal 5
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v t e

The 1908 United States presidential election in Vermont took place on November 3, 1908 as part of the 1908 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont overwhelmingly voted for the Republican nominees, Secretary of War William Howard Taft of Ohio and his running mate James S. Sherman of New York. They defeated the Democratic nominees, former U.S. Representative William Jennings Bryan and his running mate John W. Kern of Indiana. Taft won the state by a landslide margin of 53.26%.

With 75.08% of the popular vote, Vermont would be Taft’s strongest victory in terms of percentage in the popular vote.^[1]

Bryan had previously lost Vermont to William McKinley in both 1896 and 1900.