1912 United States presidential election in Arkansas

1912 United States presidential election in Arkansas

← 1908 November 5, 1912 1916 →
 
Nominee Woodrow Wilson William Howard Taft
Party Democratic Republican
Home state New Jersey Ohio
Running mate Thomas R. Marshall Nicholas M. Butler
Electoral vote 9 0
Popular vote 68,814 25,585
Percentage 55.01% 20.45%

 
Nominee Theodore Roosevelt Eugene V. Debs
Party Progressive Socialist
Home state New York Indiana
Running mate Hiram Johnson Emil Seidel
Electoral vote 0 0
Popular vote 21,644 8,153
Percentage 17.30% 6.52%

County Results

President before election

William Howard Taft
Republican

Elected President

Woodrow Wilson
Democratic

The 1912 United States presidential election in Arkansas took place on November 5, 1912, as part of the 1912 United States presidential election. Voters chose nine representatives, or electors, to the Electoral College, who voted for president and vice president.

Arkansas was won by Princeton University President Woodrow Wilson (DVirginia), running with governor of Indiana Thomas R. Marshall, with 55.01 percent of the popular vote, against the 27th president of the United States William Howard Taft (ROhio), running with Columbia University President Nicholas Murray Butler, with 20.45 percent, the 26th president of the United States Theodore Roosevelt (PNew York), running with governor of California Hiram Johnson, with 17.30 percent, and the five-time candidate of the Socialist Party of America for President of the United States Eugene V. Debs (SIndiana), running with the first Socialist mayor of a major city in the United States Emil Seidel, with 6.52 percent.[1]

  1. ^ "1912 Presidential Election Results – Arkansas". Dave Leip’s U.S. Election Atlas.

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