1912 United States presidential election in Nebraska

1912 United States presidential election in Nebraska

← 1908 November 5, 1912 1916 →
 
Nominee Woodrow Wilson Theodore Roosevelt William Howard Taft
Party Democratic Progressive Republican
Home state New Jersey New York Ohio
Running mate Thomas R. Marshall Hiram Johnson Nicholas M. Butler
Electoral vote 8 0 0
Popular vote 109,008 72,681 54,226
Percentage 43.69% 29.13% 21.74%

County Results

President before election

William Howard Taft
Republican

Elected President

Woodrow Wilson
Democratic

The 1912 United States presidential election in Nebraska took place on November 5, 1912, as part of the 1912 United States presidential election. Voters chose eight representatives, or electors, to the Electoral College, who voted for president and vice president.

Nebraska was won by Princeton University President Woodrow Wilson (DVirginia), running with governor of Indiana Thomas R. Marshall, with 43.69% of the popular vote, against the 26th president of the United States Theodore Roosevelt (PNew York), running with governor of California Hiram Johnson, with 29.13% of the popular vote and the 27th president of the United States William Howard Taft (ROhio), running with Columbia University President Nicholas Murray Butler, with 21.74% of the popular vote.[1] This was the first time in history that a nationally-successful Democratic presidential nominee carried Nebraska, as well as only the third occasion that any Democratic nominee carried the state.

  1. ^ "1912 Presidential Election Results – Nebraska".

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