1912 United States presidential election in Pennsylvania

1912 United States presidential election in Pennsylvania

← 1908 November 5, 1912 1916 →
 
Nominee Theodore Roosevelt Woodrow Wilson
Party Progressive Democratic
Home state New York New Jersey
Running mate Hiram Johnson Thomas R. Marshall
Electoral vote 38 0
Popular vote 444,894 395,637
Percentage 36.53% 32.49%

 
Nominee William Howard Taft Eugene V. Debs
Party Republican Socialist
Home state Ohio Indiana
Running mate Nicholas M. Butler Emil Seidel
Electoral vote 0 0
Popular vote 273,360 83,614
Percentage 22.45% 6.87%

County Results

President before election

William Howard Taft
Republican

Elected President

Woodrow Wilson
Democratic

The 1912 United States presidential election in Pennsylvania took place on November 5, 1912 as part of the 1912 United States presidential election. This was the first time that Arizona and New Mexico took part in a presidential election having been admitted to the Union earlier in the year. Voters chose 38 representatives, or electors to the Electoral College, who voted for president and vice president.

This election was a 4-way contest. Pennsylvania voted for the Progressive nominee former President Theodore "Teddy" Roosevelt over the Democratic nominee New Jersey Governor Woodrow Wilson, Republican nominee President William Howard Taft, and Socialist Party of America nominee union leader Eugene V. Debs. Roosevelt won Pennsylvania by a margin of 4.04%. He also became the first non-Republican candidate to win Pennsylvania since Democratic candidate and native son James Buchanan won the state in 1856.

As of the 2020 presidential election, this is the last election in which Wayne County, Snyder County, and Union County did not vote for the Republican candidate.[1]

  1. ^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

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