1928 United States presidential election in Arizona

1928 United States presidential election in Arizona

← 1924 November 6, 1928[1] 1932 →

All 3 Arizona votes to the Electoral College
 
Nominee Herbert Hoover Al Smith
Party Republican Democratic
Home state California New York
Running mate Charles Curtis Joseph T. Robinson
Electoral vote 3 0
Popular vote 52,533 38,537
Percentage 57.57% 42.23%

County Results

President before election

Calvin Coolidge
Republican

Elected President

Herbert Hoover
Republican

The 1928 United States presidential election in Arizona took place on November 6, 1928, as part of the 1928 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

Arizona was won by former U.S. Secretary of Commerce Herbert Hoover (RCalifornia), running with U.S. Senator from Kansas Charles Curtis, with 57.57% of the popular vote, against Governor of New York Al Smith (DNew York), running with U.S. Senator from Arkansas Joseph Taylor Robinson, with 42.23% of the popular vote.[2][3]

Hoover would be the final Republican presidential candidate to win Arizona, or to even carry a single county in the state, until Dwight D. Eisenhower in 1952.

  1. ^ "United States Presidential election of 1928 – Encyclopædia Britannica". Retrieved November 23, 2017.
  2. ^ "1928 Presidential General Election Results – Arizona". Retrieved November 23, 2017.
  3. ^ "The American Presidency Project – Election of 1928". Retrieved November 23, 2017.

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