1940 United States presidential election in Idaho

1940 United States presidential election in Idaho

← 1936 November 5, 1940[1] 1944 →

All 4 Idaho votes to the Electoral College
 
Nominee Franklin D. Roosevelt Wendell Willkie
Party Democratic Republican
Home state New York New York
Running mate Henry A. Wallace Charles L. McNary
Electoral vote 4 0
Popular vote 127,842 106,553
Percentage 54.36% 45.31%

County Results

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1940 United States presidential election in Idaho took place on November 5, 1940, as part of the 1940 United States presidential election. State voters chose four[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Idaho was won by incumbent President Franklin D. Roosevelt (DNew York), running with Secretary of Agriculture Henry A. Wallace, with 54.36% of the popular vote, against Wendell Willkie (RNew York), running with Minority Leader Charles L. McNary, with 45.31% of the popular vote.[3][4]

As of the 2020 presidential election, this is the last occasion when Cassia County, Lemhi County and Owyhee County have voted for a Democratic presidential candidate.[5][6]

  1. ^ "United States Presidential election of 1940 - Encyclopædia Britannica". Retrieved August 20, 2018.
  2. ^ "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved August 20, 2018.
  3. ^ "1940 Presidential General Election Results – Idaho". Retrieved August 20, 2018.
  4. ^ "The American Presidency Project – Election of 1940". Retrieved August 20, 2018.
  5. ^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016
  6. ^ Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 178-179 ISBN 0786422173

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