1940 United States presidential election in Kansas

1940 United States presidential election in Kansas

← 1936 November 5, 1940[1] 1944 →

All 9 Kansas votes to the Electoral College
 
Nominee Wendell Willkie Franklin D. Roosevelt
Party Republican Democratic
Home state New York New York
Running mate Charles L. McNary Henry A. Wallace
Electoral vote 9 0
Popular vote 489,169 364,725
Percentage 56.86% 42.40%

County Results

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1940 United States presidential election in Kansas took place on November 5, 1940, as part of the 1940 United States presidential election. Voters chose nine[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Kansas was won by Wendell Willkie (RNew York), running with Minority Leader Charles L. McNary, with 56.86 percent of the popular vote, against incumbent President Franklin D. Roosevelt (DNew York), running with Secretary Henry A. Wallace, with 42.40 percent of the popular vote.[3][4] This was the first time since 1896 that Kansas voted for a losing candidate, and the first time since 1884 that the state backed a losing Republican in a presidential election.

With 56.86 percent of the popular vote, Kansas would prove to be Willkie's third strongest state in the 1940 election in terms of popular vote percentage after South Dakota and neighboring Nebraska.[5]

  1. ^ "United States Presidential election of 1940 — Encyclopædia Britannica". Retrieved August 19, 2018.
  2. ^ "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved August 19, 2018.
  3. ^ "1940 Presidential General Election Results — Kansas". Retrieved August 19, 2018.
  4. ^ "The American Presidency Project — Election of 1940". Retrieved August 19, 2018.
  5. ^ "1940 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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