1940 United States presidential election in Kentucky

1940 United States presidential election in Kentucky

← 1936 November 5, 1940[1] 1944 →

All 11 Kentucky votes to the Electoral College
 
Nominee Franklin D. Roosevelt Wendell Willkie
Party Democratic Republican
Home state New York New York
Running mate Henry A. Wallace Charles L. McNary
Electoral vote 11 0
Popular vote 557,332 410,384
Percentage 57.45% 42.3%

County Results

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1940 United States presidential election in Kentucky took place on November 5, 1940, as part of the 1940 United States presidential election. Kentucky voters chose 11[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Kentucky was won by incumbent President Franklin D. Roosevelt (DNew York), running with Secretary Henry A. Wallace, with 57.45 percent of the popular vote, against Wendell Willkie (RNew York), running with Minority Leader Charles L. McNary, with 42.30 percent of the popular vote.[3][4]

  1. ^ "United States Presidential election of 1940 – Encyclopædia Britannica". Retrieved August 20, 2018.
  2. ^ "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved August 20, 2018.
  3. ^ "1940 Presidential General Election Results – Kentucky". Retrieved August 20, 2018.
  4. ^ "The American Presidency Project – Election of 1940". Retrieved August 20, 2018.

© MMXXIII Rich X Search. We shall prevail. All rights reserved. Rich X Search