1948 United States presidential election in Colorado

1948 United States presidential election in Colorado

← 1944 November 2, 1948[1] 1952 →

All 6 Colorado votes to the Electoral College
 
Nominee Harry S. Truman Thomas Dewey
Party Democratic Republican
Home state Missouri New York
Running mate Alben W. Barkley Earl Warren
Electoral vote 6 0
Popular vote 267,288 239,714
Percentage 51.88% 46.52%

County Results

President before election

Harry S. Truman
Democratic

Elected President

Harry S. Truman
Democratic

The 1948 United States presidential election in Colorado took place on November 2, 1948, as part of the 1948 United States presidential election. State voters chose six[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Colorado was won by incumbent President Harry S. Truman (DMissouri), running with Senator Alben W. Barkley, with 51.88% of the popular vote, against Governor Thomas Dewey (RNew York), running with Governor Earl Warren, with 46.52% of the popular vote.[3][4] As of the 2020 election, Truman remains the last candidate to carry Colorado without winning Larimer County, as well as the last Democrat to win the national election without Adams County. Colorado also marks Truman's strongest performance in a state that Dewey had won against Franklin D. Roosevelt in 1944. This was the only election between 1900 and 1992 in which Colorado voted differently than neighboring Nebraska.

  1. ^ "United States Presidential election of 1948 - Encyclopædia Britannica". Retrieved October 25, 2017.
  2. ^ "1948 Election for the Forty-First Term (1949-53)". Retrieved October 25, 2017.
  3. ^ "1948 Presidential General Election Results - Colorado". Retrieved October 25, 2017.
  4. ^ "The American Presidency Project - Election of 1948". Retrieved October 25, 2017.

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