1948 United States presidential election in Oregon

1948 United States presidential election in Oregon
All 6 Oregon votes to the Electoral College
Dewey 40-50% 50-60% 60-70%	Truman 40-50% 50-60%
President before election; Harry S. Truman; Democratic	Elected President ; Harry S. Truman; Democratic

The 1948 United States presidential election in Oregon took place on November 2, 1948, as part of the 1948 United States presidential election. Voters chose six^[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Oregon was won by Governor Thomas Dewey (R–New York), running with Governor Earl Warren, with 49.78% of the popular vote, against incumbent President Harry S. Truman (D–Missouri), running with Senator Alben W. Barkley, with 46.40% of the popular vote.^[3]^[4]

Dewey’s victory was the first of four consecutive Republican victories in the state, as Oregon would not vote Democratic again until Lyndon B. Johnson’s 1964 landslide victory.

This was the last election until 1988 in which Oregon and California did not vote for the same candidate and, as of 2020, it has not happened again.

^ "United States Presidential election of 1948 - Encyclopædia Britannica". Retrieved December 20, 2017.
^ "1948 Election for the Forty-First Term (1949-53)". Retrieved December 20, 2017.
^ "1948 Presidential General Election Results – Oregon". Retrieved December 20, 2017.
^ "The American Presidency Project - Election of 1948". Retrieved December 20, 2017.

[1] "United States Presidential election of 1948 - Encyclopædia Britannica". Retrieved December 20, 2017.

[2] "1948 Election for the Forty-First Term (1949-53)". Retrieved December 20, 2017.

[3] "1948 Presidential General Election Results – Oregon". Retrieved December 20, 2017.

[4] "The American Presidency Project - Election of 1948". Retrieved December 20, 2017.

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