1988 United States Senate election in Ohio

1988 United States Senate election in Ohio

← 1982 November 8, 1988 1994 →
 
Nominee Howard Metzenbaum George Voinovich
Party Democratic Republican
Popular vote 2,480,038 1,872,716
Percentage 56.97% 42.31%


Metzenbaum:      50–60%      60–70%      70–80%
Voinovich:      50–60%      60–70%

U.S. senator before election

Howard Metzenbaum
Democratic

Elected U.S. Senator

Howard Metzenbaum
Democratic

The 1988 United States Senate election in Ohio was held on November 8, 1988. Incumbent Democratic U.S. Senator Howard Metzenbaum won re-election.[1] Metzenbaum easily won the Democratic nomination with over 80% of the vote, while Cleveland Mayor George Voinovich was uncontested in his primary. This was the last U.S. senator to win in the Democratic party at this seat until 2006. In addition, Metzenbaum's 56.97% of the vote is to date the best performance for a Democrat running for the U.S. Senate in Ohio, though Sherrod Brown, a Democrat nearly broke that in 2006. Voinovich would later be elected in the other Senate seat ten years later. As of 2023, this remains the last time that Ohio would support different parties in concurrent presidential and Senate elections.

  1. ^ "Our Campaigns - OH US Senate Race - Nov 08, 1988".

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