1992 United States presidential election in West Virginia

1992 United States presidential election in West Virginia
Clinton 40–50% 50–60% 60–70% 70–80%	Bush 30–40% 40–50% 50–60% 60–70%
President before election; George H. W. Bush; Republican	Elected President ; Bill Clinton; Democratic

The 1992 United States presidential election in West Virginia took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

West Virginia was won by Governor Bill Clinton (D-Arkansas) with 48.41% of the popular vote over incumbent President George H. W. Bush (R-Texas) with 35.39%. Businessman Ross Perot (I-Texas) finished in third, with 15.92% of the popular vote.^[1] Clinton ultimately won the national vote, defeating incumbent President Bush.^[2]

As of the 2020 presidential election^[update], this is the last election in which Wirt County voted for a Democratic presidential candidate.

^ Cite error: The named reference results was invoked but never defined (see the help page).
^ "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved June 11, 2012.