1993 Major League Baseball postseason

1993 Major League Baseball postseason
Tournament details
DatesOctober 5–23, 1993[1]
Teams4
Final positions
ChampionsToronto Blue Jays
(2nd title)
Runner-upPhiladelphia Phillies
(5th World Series appearance)
Tournament statistics
MVPPaul Molitor
(TOR)
← 1992
1995 →

The 1993 Major League Baseball postseason was the playoff tournament of Major League Baseball for the 1993 season. The winners of each division advance to the postseason and face each other in a League Championship Series to determine the pennant winners that face each other in the World Series. This was the last edition of the postseason to feature only two rounds, with only division champions qualifying. After the 1994-95 Major League Baseball strike, the playoffs were expanded to include a wild card team and a new League Division Series for the 1995 postseason.

The Toronto Blue Jays and Atlanta Braves both returned to the postseason for the third year in a row, while the Chicago White Sox and Philadelphia Phillies returned for the first time in a decade. This would be the last appearance for the Phillies until 2007, as well as Toronto's last appearance until 2015.

This was the last edition of the postseason until 2008 to not feature the New York Yankees, who would make thirteen straight postseason appearances from 1995 to 2007. It also marked the second time in three years that the postseason did not feature a team from California.

The playoffs began on October 5, 1993, and concluded on October 23, 1993, with the Blue Jays defeating the Phillies in six games in the 1993 World Series. The Blue Jays repeated as World Series champions, becoming the seventh franchise in MLB history to win back-to-back championships.[2]

  1. ^ "1993 Major Leagues Schedule". Baseball-Reference.com. Retrieved July 11, 2022.
  2. ^ Adler, David (November 6, 2021). "Every back-to-back World Series champ". MLB.com. Retrieved July 12, 2022.

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