1996 United States presidential election in Kentucky

1996 United States presidential election in Kentucky

← 1992 November 5, 1996 2000 →
 
Nominee Bill Clinton Bob Dole Ross Perot
Party Democratic Republican Reform
Home state Arkansas Kansas Texas
Running mate Al Gore Jack Kemp Patrick Choate
Electoral vote 8 0 0
Popular vote 636,614 623,283 120,396
Percentage 45.84% 44.88% 8.67%

County Results

President before election

Bill Clinton
Democratic

Elected President

Bill Clinton
Democratic

The 1996 United States presidential election in Kentucky took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for president and vice president.

Kentucky was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 45.84% to 44.88% by a slim margin of 0.96%, thus marking Kentucky the closest contest in the entire election. Billionaire businessman Ross Perot (Reform-TX) finished in third, with 8.67% of the popular vote.[1]

As of the 2020 presidential election, this is the last time that the Democratic nominee carried Kentucky, as well as any of these 36 counties: Powell, Montgomery, Nicholas, Lawrence, Bourbon, Nelson, Simpson, McCracken, Hopkins, Calloway, Graves, Greenup, Clark, Marshall, Meade, Bell, Logan, Ohio, Johnson, Marion, Harrison, Henry, Union, Trigg, Morgan, Webster, Caldwell, Martin, Carroll, McLean, Livingston, Trimble, Gallatin, Lyon, Carlisle, and Hickman. This is also the last time that the Republican presidential nominee did not win more than 56% of the vote in Kentucky.

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