1996 United States presidential election in Wisconsin

1996 United States presidential election in Wisconsin

← 1992 November 5, 1996 2000 →
 
Nominee Bill Clinton Bob Dole Ross Perot
Party Democratic Republican Reform
Home state Arkansas Kansas Texas
Running mate Al Gore Jack Kemp Patrick Choate
Electoral vote 11 0 0
Popular vote 1,071,971 845,029 227,339
Percentage 48.81% 38.48% 10.35%


President before election

Bill Clinton
Democratic

Elected President

Bill Clinton
Democratic

The 1996 United States presidential election in Wisconsin took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for president and vice president.

Wisconsin was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning by 48.81% to 38.48%, or a margin of 10.33%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third, with 10.35% of the popular vote.[1]

As of the 2020 presidential election, this is the last election in which the following counties have voted for a Democratic presidential candidate: Polk, St. Croix, Sheboygan, and Taylor.[2]


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