2008 United States presidential election in Rhode Island

2008 United States presidential election in Rhode Island

← 2004 November 4, 2008 2012 →
Turnout66.9%[1] Increase 4.8 pp
 
Nominee Barack Obama John McCain
Party Democratic Republican
Home state Illinois Arizona
Running mate Joe Biden Sarah Palin
Electoral vote 4 0
Popular vote 296,571 165,391
Percentage 62.86% 35.06%


President before election

George W. Bush
Republican

Elected President

Barack Obama
Democratic

The 2008 United States presidential election in Rhode Island took place on November 4, 2008, and was part of the 2008 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Rhode Island was won by Democratic nominee Barack Obama with a 27.8% margin of victory. Prior to the election, all 17 news organizations considered this a state Obama would win, or otherwise considered as a safe blue state. At the time, the last time a Republican had carried this state or any county in it was in 1984, when Ronald Reagan won with about 52% of the vote, largely due to the support of Reagan Democrats.

  1. ^ This figure is calculated by dividing the total number of votes cast in 2008 (469,767) by an estimate of the number of registered voters in Rhode Island in 2008 (701,307).
    • For the number of votes cast, see "Official 2008 Presidential General Election Results". Rhode Island Board of Elections. November 17, 2008. Retrieved February 6, 2018.
    • For the estimated number of registered voters, see "Eligible Voter October 4, 2008" (PDF). Rhode Island Board of Elections. October 4, 2008. Retrieved February 6, 2018.

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