Truncated octahedron

Truncated octahedron
(Click here for rotating model)
Type	Archimedean solid Uniform polyhedron
Elements	F = 14, E = 36, V = 24 (χ = 2)
Faces by sides	6{4}+8{6}
Conway notation	tO bT
Schläfli symbols	t{3,4} tr{3,3} or ${\displaystyle t{\begin{Bmatrix}3\\3\end{Bmatrix}}}$
	t0,1{3,4} or t0,1,2{3,3}
Wythoff symbol	2 4 | 3 3 3 2 |
Coxeter diagram
Symmetry group	Oh, B3, [4,3], (*432), order 48 Th, [3,3] and (*332), order 24
Rotation group	O, [4,3]+, (432), order 24
Dihedral angle	${\displaystyle {\begin{aligned}{\text{4-6:}}&\ \arccos {\tfrac {-1}{\sqrt {3}}}=125^{\circ }15'51''\\{\text{6-6:}}&\ \arccos {\tfrac {-1}{3}}=109^{\circ }28'16''\end{aligned}}}$
References	U08, C20, W7
Properties	Semiregular convex parallelohedron permutohedron zonohedron
Colored faces	4.6.6 (Vertex figure)
Tetrakis hexahedron (dual polyhedron)	Net

In geometry, the truncated octahedron is the Archimedean solid that arises from a regular octahedron by removing six pyramids, one at each of the octahedron's vertices. The truncated octahedron has 14 faces (8 regular hexagons and 6 squares), 36 edges, and 24 vertices. Since each of its faces has point symmetry the truncated octahedron is a 6-zonohedron. It is also the Goldberg polyhedron G_IV(1,1), containing square and hexagonal faces. Like the cube, it can tessellate (or "pack") 3-dimensional space, as a permutohedron.

The truncated octahedron was called the "mecon" by Buckminster Fuller.^[1]

Its dual polyhedron is the tetrakis hexahedron. If the original truncated octahedron has unit edge length, its dual tetrakis hexahedron has edge lengths ⁠9/8⁠√2 and ⁠3/2⁠√2.