1868 United States presidential election in Kentucky

1868 United States presidential election in Kentucky
← 1864 November 3, 1868 1872 →
 
Nominee Horatio Seymour Ulysses S. Grant
Party Democratic Republican
Home state New York Illinois
Running mate Francis Preston Blair, Jr. Schuyler Colfax
Electoral vote 11 0
Popular vote 115,889 39,566
Percentage 74.55% 25.45%

County Results

President before election

Andrew Johnson
Democratic

Elected President

Ulysses S. Grant
Republican

The 1868 United States presidential election in Kentucky took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for president and vice president.

Kentucky voted for the Democratic nominee, Horatio Seymour over the Republican nominee, Ulysses S. Grant. Seymour won the state by a margin of 49.1%.

With 74.55% of the popular vote, Kentucky would be Seymour's strongest victory in terms of percentage in the popular vote.[1] As of the 2020 presidential election, this remains the strongest-ever performance by a presidential nominee in Kentucky who had a major-party opponent since the First Party System, when Democratic-Republicans regularly routed Federalists with over 90% of the vote. It was also the last time that Clinton County or Cumberland County would vote for a Democratic presidential candidate.[2]

  1. ^ "1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. ^ Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 207-213 ISBN 0786422173

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