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| Elections in Oregon |
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The 1992 United States presidential election in Oregon took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.
Oregon was won by Governor Bill Clinton (D-Arkansas) with 42.48% of the popular vote over incumbent President George H. W. Bush (R-Texas) with 32.53%. Businessman Ross Perot (I-Texas) finished in third, with 24.21% of the popular vote.[1] Clinton ultimately won the national vote, defeating incumbent President Bush.[2]
As of the 2020 presidential election[update], this is the last time that Curry and Jefferson counties have voted for the Democratic nominee.[3] It was also the first election since 1888 when Crook County had not backed the winning candidate, although Bush’s margin was less than 200 votes and was only a plurality. Nevertheless, this would mark the county becoming a Republican bastion.[4] Deschutes County, which was narrowly won by Clinton via plurality, would not vote for a Democrat again until 2020.
- ^ Cite error: The named reference
resultswas invoked but never defined (see the help page). - ^ "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved June 9, 2012.
- ^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016
- ^ Lewis-Beck; Michael S.; ‘Election Forecasts in 1984: How Accurate Were They’; Political Science and Politics 18(1) (January 1985), pp. 53-63
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