1900 United States presidential election in Nebraska

1900 United States presidential election in Nebraska

← 1896 November 6, 1900 1904 →
 
Nominee William McKinley William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Theodore Roosevelt Adlai Stevenson I
Electoral vote 8 0
Popular vote 121,835 114,013
Percentage 50.46% 47.22%

County Results

President before election

William McKinley
Republican

Elected President

William McKinley
Republican

The 1900 United States presidential election in Nebraska took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. Voters chose eight electors to the Electoral College, which selected the president and vice president.

Nebraska was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York. They defeated the Democratic nominees, former U.S. Representative, 1896 Democratic presidential nominee and Nebraska native William Jennings Bryan and his running mate, former Vice President Adlai Stevenson I. McKinley won the state by a narrow margin of 3.24% in this rematch of the 1896 presidential election. The return of economic prosperity and recent victory in the Spanish–American War helped McKinley to score a decisive victory.

Bryan had previously defeated McKinley in the state four years earlier and would later win it again against William Howard Taft in 1908.


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