1948 United States presidential election in Kansas

1948 United States presidential election in Kansas

← 1944 November 2, 1948[1] 1952 →

All 8 Kansas votes to the Electoral College
 
Nominee Thomas Dewey Harry S. Truman
Party Republican Democratic
Home state New York Missouri
Running mate Earl Warren Alben W. Barkley
Electoral vote 8 0
Popular vote 423,039 351,902
Percentage 53.63% 44.61%

County Results

President before election

Harry S. Truman
Democratic

Elected President

Harry S. Truman
Democratic

The 1948 United States presidential election in Kansas took place on November 2, 1948, as part of the 1948 United States presidential election. Voters chose eight[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Kansas was won by Governor Thomas Dewey (RNew York), running with Governor Earl Warren, with 53.63 percent of the popular vote, against incumbent President Harry S. Truman (DMissouri), running with Senator Alben W. Barkley, with 44.61 percent of the popular vote.[3][4]

With 53.63 percent of the popular vote, Kansas would prove to be Dewey's fourth strongest state in the nation after Vermont, Maine and Nebraska.[5]

  1. ^ "United States Presidential election of 1948 - Encyclopædia Britannica". Retrieved December 20, 2017.
  2. ^ "1948 Election for the Forty-First Term (1949-53)". Retrieved December 20, 2017.
  3. ^ "1948 Presidential General Election Results -Kansas". Retrieved December 20, 2017.
  4. ^ "The American Presidency Project - Election of 1948". Retrieved December 20, 2017.
  5. ^ "1948 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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