1948 United States presidential election in Montana

1948 United States presidential election in Montana

← 1944 November 2, 1948 1952 →
 
Nominee Harry S. Truman Thomas E. Dewey
Party Democratic Republican
Home state Missouri New York
Running mate Alben W. Barkley Earl Warren
Electoral vote 4 0
Popular vote 119,071 96,770
Percentage 53.09% 43.15%

County Results

President before election

Harry S. Truman
Democratic

Elected President

Harry S. Truman
Democratic

The 1948 United States presidential election in Montana took place on November 2, 1948 as part of the 1948 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Montana voted for the Democratic nominee, President Harry S. Truman, over the Republican nominee, New York Governor Thomas E. Dewey. Truman won Montana by a substantial margin of 9.94%. As of the 2020 presidential election, this is the last election in which Carter County and Prairie County voted for a Democratic presidential candidate.[1] As of the 2020 presidential election, this (and the prior election) mark the last time that Montana has voted Democratic in two consecutive presidential elections.

  1. ^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

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