1996 United States presidential election in Utah

1996 United States presidential election in Utah
Dole 40-50% 50-60% 60-70% 70-80%	Clinton 40-50% 50-60%
President before election; Bill Clinton; Democratic	Elected President ; Bill Clinton; Democratic

The 1996 United States presidential election in Utah took place on November 7, 1996, as part of the 1996 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Utah was won by Republican nominee Bob Dole by a 21.07 percent margin of victory. This was Dole’s highest margin of victory for any state in the country.^[1] Dole also obtained 54.37 percent of the vote in Utah, higher than any other state.^[2]

As of the 2020 presidential election^[update], this is the last election in which Tooele County and Carbon County voted for a Democratic presidential candidate.^[3] This also marked the first time since statehood that a president won two terms without ever carrying Utah.

^ "1996 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
^ Dave Leip’s U.S. Election Atlas; 1996 Presidential General Election Results – Utah
^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

[1] "1996 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

[2] Dave Leip’s U.S. Election Atlas; 1996 Presidential General Election Results – Utah

[how-3] Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

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