1940 Democratic National Convention

1940 Democratic National Convention
1940 presidential election
Nominees
Roosevelt and Wallace
Convention
Date(s)July 15–18, 1940
CityChicago, Illinois
VenueChicago Stadium
Candidates
Presidential nomineeFranklin D. Roosevelt of New York
Vice presidential nomineeHenry A. Wallace of Iowa
Voting
Total delegates1093
Votes needed for nomination547 (majority)
Results (president)Roosevelt (NY): 946 (86.32%)
Farley (NY): 72 (6.57%)
Garner (TX): 61 (5.57%)
Tydings (MD): 9 (0.82%)
Cordell Hull (TN): 5 (0.47%)
Results (vice president)Wallace (IA): 626 (59.3%)
Bankhead (AL): 329 (31.17%)
McNutt (IN): 68 (6.44%)
Others: 32.5 (3.07%)
‹ 1936 · 1944 ›

The 1940 Democratic National Convention was held at the Chicago Stadium in Chicago, Illinois from July 15 to July 18, 1940. The convention resulted in the nomination of President Franklin D. Roosevelt for an unprecedented third term. Secretary of Agriculture Henry A. Wallace from Iowa was nominated for vice president.

Despite the unprecedented bid for a third term, Roosevelt was nominated on the first ballot. Roosevelt's most formidable challengers were his former campaign manager James Farley and Vice President John Nance Garner. Both had sought the nomination for the presidency and soundly lost to Roosevelt who would be "drafted" at the convention. Henry Wallace was Roosevelt's preferred choice for the vice presidency. His candidacy was opposed vehemently by some delegates, particularly the conservative wing of the party which had been unenthusiastic about Wallace's liberal positions. Nonetheless, Wallace was ultimately nominated with the votes of 59% of the delegates, on the first ballot.[1]

  1. ^ "The 1940 Democratic National Convention". Chicago Historical Society. Archived from the original on 2008-07-23. Retrieved 2008-03-27.

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