1996 United States presidential election in Alaska

1996 United States presidential election in Alaska
Dole 40–50% 50–60% 60–70%	Clinton 30–40% 40–50% 50–60%
President before election; Bill Clinton; Democratic	Elected President ; Bill Clinton; Democratic

The 1996 United States presidential election in Alaska took place on November 7, 1996, as part of the 1996 United States presidential election. Voters chose representatives, or electors to the Electoral College, who voted for president and vice president.

Alaska was won by Senator Bob Dole (R-KS), with Dole winning 50.80% to 33.27% over President Bill Clinton (D) by a margin of 17.53%.^[1] Billionaire businessman Ross Perot (Reform-TX) finished in third, with 10.9% of the popular vote.

With 50.8% of the popular vote, Alaska proved to be Dole's fifth strongest state in the 1996 election after Utah, Kansas, Nebraska and Idaho.^[2]

^ Cite error: The named reference Atlas was invoked but never defined (see the help page).
^ "1996 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.