1845 Florida's at-large congressional district special election

1845 Florida's at-large congressional district special election

← 1845 October 6, 1845 1846 →
 
Nominee Edward Carrington Cabell William Henry Brockenbrough
Party Whig Democratic
Popular vote 2,523 2,472
Percentage 50.51% 49.49%

Representative-elect before election

David Levy Yulee
Democratic

Elected U.S. Representative

Edward Carrington Cabell
Whig

1845 Florida's at-large congressional district special election recount

January 24, 1846
 
Nominee William Henry Brockenbrough Edward Carrington Cabell
Party Democratic Whig
Popular vote 2,669 2,632
Percentage 50.35% 49.65%

County results
Brockenbrough:      50–60%      60–70%      70–80%      80–90%      >90%
Cabell:      50–60%      60–70%      70–80%
     No Votes

Representative before election

Edward Carrington Cabell
Whig

Elected Representative

William Henry Brockenbrough
Democratic

A special election to the United States House of Representatives for Florida's at-large congressional district was held October 6, 1845.[1]

The winning candidate would serve a less-than-two-year term in the United States House of Representatives to represent Florida in the 29th Congress from October 6, 1845, to March 4, 1847.

The election was initially called for the Whig candidate, Edward Carrington Cabell, and Cabell was seated in the House of Representatives. However, a recount found the winner to actually be the Democratic candidate, William Henry Brockenbrough. Brockenbrough was seated immediately on January 24, 1846.[2][3]

  1. ^ "FL At Large - Special Election Race - Oct 06, 1845". Our Campaigns. Retrieved October 17, 2020.
  2. ^ "FL At Large - Special Election Recount Race - Jan 24, 1846". Our Campaigns. Retrieved October 17, 2020.
  3. ^ "TWENTY-NINTH CONGRESS" (PDF). United States House of Representatives. March 9, 2013. Archived from the original (PDF) on March 9, 2013. Retrieved October 16, 2020.

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