1858 United States House of Representatives election in Florida

1858 United States House of Representatives election in Florida

← 1856 October 4, 1858 1860 →
 
Nominee George Sydney Hawkins John Westcott
Party Democratic Independent Democratic
Popular vote 6,084 3,661
Percentage 62.43% 37.57%

County Results

Representative before election

George Sydney Hawkins
Democratic

Elected Representative


George Sydney Hawkins
Democratic

The 1858 United States House of Representatives election in Florida was held on Monday, October 4, 1858 to elect the single United States Representative from the state of Florida, one from the state's single at-large congressional district, to represent Florida in the 36th Congress. The election coincided with the elections of other offices, including various state and local elections.

The winning candidate would serve a two-year term in the United States House of Representatives from March 4, 1859, to March 4, 1861.[1]

  1. ^ "Our Campaigns - FL At Large Race - Oct 04, 1858". www.ourcampaigns.com. Retrieved November 7, 2020.

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