1928 United States presidential election in Pennsylvania

1928 United States presidential election in Pennsylvania
Hoover 50-60% 60-70% 70-80% 80-90%	Smith 50-60%
President before election; Calvin Coolidge; Republican	Elected President ; Herbert Hoover; Republican

The 1928 United States presidential election in Pennsylvania took place on November 6, 1928 as part of the 1928 United States presidential election. Voters chose 38 representatives, or electors to the Electoral College, who voted for president and vice president.

Pennsylvania overwhelmingly voted for the Republican nominee, former U.S. Secretary of Commerce Herbert Hoover, over the Democratic nominee, New York Governor Al Smith. Hoover won Pennsylvania by a landslide margin of 31.35%. The Republicans at this time were associated with the booming economy of the 1920s while Smith was associated with the corruption of Tammany Hall.

Despite losing the state, Smith flipped 3 majority-Catholic counties that voted for Calvin Coolidge in 1924 and had been consistently Republican during the "System of 1896" into the Democratic column: Elk, Lackawanna, and Luzerne.^[1] This came with losing the 4 counties – all dominated by profoundly anti-Catholic Appalachian Protestants^[2] – that voted for John W. Davis to Hoover: Columbia, Fulton, Greene, and Monroe. Hoover was the first ever Republican to carry Columbia, Greene, and Monroe counties.

^ Phillips, Kevin P; The Emerging Republican Majority, p. 41 ISBN 978-0-691-16324-6
^ Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 58-60 ISBN 0786422173

[1] Phillips, Kevin P; The Emerging Republican Majority, p. 41 ISBN 978-0-691-16324-6

[2] Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 58-60 ISBN 0786422173

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