1988 United States presidential election in Tennessee

1988 United States presidential election in Tennessee
Bush 40–50% 50–60% 60–70% 70–80%	Dukakis 40–50% 50–60% 60–70%
President before election; Ronald Reagan; Republican	Elected President ; George H. W. Bush; Republican

The 1988 United States presidential election in Tennessee took place on November 8, 1988. All 50 states and the District of Columbia were part of the 1988 United States presidential election. Tennessee voters chose 11 electors to the Electoral College, which selected the president and vice president. Tennessee was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.

Tennessee weighed in for this election as eight points more Republican than the national average. Tennessee was the only state to vote more Republican than in 1984. As of the 2020 presidential election^[update], this was the last time the Republican candidate carried Davidson County (home of Nashville) and Shelby County (home of Memphis), both of which have become staunch, and the only, Democratic strongholds into the 21st century.^[1]

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