1896 United States presidential election in Alabama

1896 United States presidential election in Alabama

← 1892 November 3, 1896 1900 →
 
Nominee William Jennings Bryan William McKinley
Party Democratic Republican
Alliance Populist
Home state Nebraska Ohio
Running mate Arthur Sewall Garret Hobart
Electoral vote 11 0
Popular vote 130,298 55,673
Percentage 66.96% 28.61%

County results

President before election

Grover Cleveland
Democratic

Elected President

William McKinley
Republican

The 1896 United States presidential election in Alabama took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. Alabama voters chose eleven electors to the Electoral College, which selected the president and vice president.

Alabama was won by the Democratic nominees, former U.S. Representative William Jennings Bryan of Nebraska and his running mate Arthur Sewall of Maine. They defeated the Republican nominees, former Governor of Ohio William McKinley and his running mate Garret Hobart of New Jersey. Bryan won the state by a margin of 38.35%.

Despite losing by more than a two-to-one margin, this would prove the last time a Republican won Colbert County until Richard Nixon in 1972.[1]

Bryan would defeat McKinley in Alabama again four years later and would later win the state again in 1908 against William Howard Taft.

  1. ^ Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 143–147 ISBN 0786422173.

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