1900 United States presidential election in Alabama

1900 United States presidential election in Alabama

← 1896 November 6, 1900 1904 →
 
Nominee William Jennings Bryan William McKinley
Party Democratic Republican
Home state Nebraska Ohio
Running mate Adlai Stevenson I Theodore Roosevelt
Electoral vote 11 0
Popular vote 97,129 55,612
Percentage 60.82% 34.82%

County results

President before election

William McKinley
Republican

Elected President

William McKinley
Republican

The 1900 United States presidential election in Alabama took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. Alabama voters chose eleven electors to the Electoral College, which selected the president and vice president.

Alabama was won by the Democratic nominees, former U.S. Representative William Jennings Bryan of Nebraska and his running mate Adlai Stevenson I of Illinois. They defeated the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York. Bryan won the state by a margin of 26%.

This would prove to be the last occasion when the Republican presidential candidate won Lauderdale and Limestone counties until Richard Nixon in 1972, the last when the Republican nominee carried Butler and Walker counties until Barry Goldwater in 1964, and the last when the Democratic nominee carried Winston County until Franklin D. Roosevelt won it by one vote in 1932.[1]

Bryan had previously defeated McKinley in Alabama four years earlier and would later win the state again in 1908 against William Howard Taft.

  1. ^ Menendez, Albert J. (2005). The Geography of Presidential Elections in the United States, 1868-2004. pp. 143–147. ISBN 0786422173..

© MMXXIII Rich X Search. We shall prevail. All rights reserved. Rich X Search